### C++ program to convert binary tree to binary search tree

Description:
1.Copy the items of binary tree in a set while doing inorder traversal. This takes O(n log n) time. Note that set in C++ STL is implemented using a Self Balancing Binary Search Tree.

2.There is no need to sort the set as sets in C++ are implemented using Self-balancing binary search trees.

3.Now simply copy the items of set one by one from beginning to the tree while doing inorder traversal of tree. Care should be taken as when copying each item of set from its beginning, we first copy it to the tree while doing inorder traversal, then remove it from the set as well.
Program:
```#include<iostream>
#include <bits/stdc++.h>
using namespace std;

struct Node
{
int data;
struct Node *left, *right;
};

void storeinorderInSet(Node* root, set<int>& s)
{
if (!root)
return;

storeinorderInSet(root->left, s);
s.insert(root->data);
storeinorderInSet(root->right, s);

}
void setToBST(set<int>& s, Node* root)
{

if (!root)
return;
setToBST(s, root->left);
auto it = s.begin();
root->data = *it;
s.erase(it);
setToBST(s, root->right);

}
void binaryTreeToBST(Node* root)
{
set<int> s;
storeinorderInSet(root, s);
setToBST(s, root);

}
Node* newNode(int data)
{

Node* temp = new Node();
temp->data = data;
temp->left = temp->right = NULL;
return temp;
}

void inorder(Node* root)
{
if (!root)
return;
inorder(root->left);
cout << root->data << " ";
inorder(root->right);
}

int main()
{
Node* root = newNode(1);
root->left = newNode(2);
root->right = newNode(5);
root->right->left = newNode(8);
root->left->left = newNode(9);
root->left->right = newNode(11);
root->right->right = newNode(43);

binaryTreeToBST(root);
cout << "Inorder traversal of BST is: " << endl;
inorder(root);
return 0;
}```

Output:
Inorder traversal of BST is: 1 2 5 8 9 11 43

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