### Python program to check if two trees are identical without using recursion

Description:
Two trees are identical if they have the same data and same arrangements of data.To identify, if two trees are identical we need to traverse both trees simultaneously, and while traversing we need to compare data  and children of trees.

Example:
It will return false as their data are not same.

It will return True as their data and structures both are same.

Program:

from queue import Queue class newNode: def __init__(self, data): self.data = data self.left = self.right = None # Iterative method to find height of Bianry Tree def areIdentical(root1, root2): # Return true if both trees are empty if (not root1 and not root2): return True # Return false if one is empty and # other is not if (not root1 or not root2): return False # Create an empty queues for simultaneous traversals q1 = Queue() q2 = Queue() # Enqueue Roots of trees in respective queues q1.put(root1) q2.put(root2) while (not q1.empty() and not q2.empty()): # Get front nodes and compare them n1 = q1.queue[0] n2 = q2.queue[0] if (n1.data != n2.data): return False # Remove front nodes from queues q1.get() q2.get() # Enqueue left children of both nodes if (n1.left and n2.left): q1.put(n1.left) q2.put(n2.left) elif (n1.left or n2.left): return False if (n1.right and n2.right): q1.put(n1.right) q2.put(n2.right) elif (n1.right or n2.right): return False return True # Driver Code if __name__ == '__main__': root1 = newNode(1) root1.left = newNode(2) root1.right = newNode(3) root1.left.left = newNode(4) root1.left.right = newNode(5) root2 = newNode(1) root2.left = newNode(2) root2.right = newNode(3) root2.left.left = newNode(4) root2.left.right = newNode(5) if areIdentical(root1, root2): print("Yes") else: print("No")

Output:
Yes
>>>

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