### Python program to check if two trees are identical using recursion.

Description:
To check whether two trees are identical or not we will check these things:
1)If both the trees are null , then return true
2) If both the trees are not null, then compare data and recursively check left and right sub-tree structure.

Program :
class BTNode: def __init__(self, data): self.data = data self.left = None self.right = None # Return true if they arc structurally identical. def areStructurallySameTrees(root1, root2): if (not root1.left) and not (root1.right) and (not root2.left) and not (root2.right) and root1.data == root2.data: return True if (root1.data != root2.data) or (root1.left and not root2. left) or (not root1.left and root2.left) or (root1.right and not root2.right) or (not root1 .right and root2.right): return False left= areStructurallySameTrees(root1.left, root2.left) if root1.left and root2.left else True right = areStructurallySameTrees(root1.right, root2. right) if root1.right and root2.right else True return left and right root1 = BTNode("A") b=BTNode("B") c= BTNode("C") d = BTNode("D") e=BTNode("E") f=BTNode("F") g=BTNode("G") root1.left=b root1.right=c b.left=d b.right=e c.left=f c.right=g root2 = BTNode("A") b=BTNode("B") c= BTNode("C") d = BTNode("D") e=BTNode("E") f=BTNode("F") g=BTNode("G") root2.left=b root2.right=c b.left=d b.right=e c.left=f c.right=g print(areStructurallySameTrees(root1,root2)) #Time Complexity: O(n). Space Complexity: O(n), for recursive stack.

Output:
True
>>>

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