C++ program to check for symmetric binary tree using recursion














































C++ program to check for symmetric binary tree using recursion



Description:
This Program is to check for symmetric binary tree using recursion
For Example:

Input :
The Elements are : 1 ,2 ,2 ,3 ,4 ,4 ,3
Output :
Symmetric binary tree

Program :

//C++ program to check for symmetric binary tree using recursion #include <bits/stdc++.h> using namespace std; // tree node struct Node { int data; Node *left, *right; }; // returns a new tree Node Node* newNode(int data) { Node* temp = new Node(); temp->data = data; temp->left = temp->right = NULL; return temp; } //return true if they are mirror bool Mirror(struct Node *root1, struct Node *root2) { // if both empty if (root1 == NULL && root2 == NULL) return true; // if both are non empty then comparing them if (root1 && root2 && root1->data == root2->data) return Mirror(root1->left, root2->right) && Mirror(root1->right, root2->left); //if false return false; } int main() { struct Node *root = newNode(1); root->left = newNode(2); root->right = newNode(2); root->left->left = newNode(3); root->left->right = newNode(4); root->right->left = newNode(4); root->right->right = newNode(3); if(Mirror(root, root)) cout<<"Symmetric binary tree."; else cout<<"Not a Symmetric binary tree."; getchar(); return 0; }



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