### Python Graphlib module static_order( )-2

In the previous article, we have seen some information about static_order( )

*The order of elements returned by static_order( ) depends on how u   inserted the elements  in the graph.
Example:
Topologicalorder-1:

`from graphlib import TopologicalSorter  ts = TopologicalSorter()  ts.add(3, 2, 1)ts.add(1, 0)  print("TopologicalOrder1=",end=" ")print([*ts.static_order()])`

Output:
`TopologicalOrder1= [2, 0, 1, 3]`

Topologicalorder-2:

`from graphlib import TopologicalSorterts2 = TopologicalSorter()ts2.add(1, 0)ts2.add(3, 2, 1)print("TopologicalOrder2=",end=" ")print([*ts2.static_order()])`

Output:
`TopologicalOrder2= [0, 2, 1, 3]`

By observing TopologicalOrder1 and TopologicalOrder2, we conclude
that order of elements depends upon order of insertion.

*If any cycles is detected in the graph, CycleError will be raised.
For Example:
`from graphlib import TopologicalSortertos = TopologicalSorter()tos.add(1, 0)tos.add(3, 2, 1)tos.add(0, 1)print([*tos.static_order()])`

Output:
`Traceback (most recent call last):  File "C:\Users\findm\AppData\Local\Programs\Python\Python39\graphlib1.py", line 15, in <module>    print([*tos.static_order()])  File "C:\Users\findm\AppData\Local\Programs\Python\Python39\lib\graphlib.py", line 242, in static_order    self.prepare()  File "C:\Users\findm\AppData\Local\Programs\Python\Python39\lib\graphlib.py", line 104, in prepare    raise CycleError(f"nodes are in a cycle", cycle)graphlib.CycleError: ('nodes are in a cycle', [1, 0, 1])`